I ran some stats for the upcoming B10 Tourney thru the 1st tiebreakers (hey, it's tax season!).
It tended to support the comments coming out of the mediots during yesterday's telecast of the RUT game, where they had both UCLA & $cum likely making the Dance as the Last Four in.
The B10 Tourney has 4 tranches, wherein UCLA holds a solid edge over $cum as the 8 seed vs their #10 seed. UCLA is 8-4 and is currently positioned to receive two byes in the Tourney vs only 1 for 6-6 Fig Tech:
Seeds 1-4 receive THREE byes;
Seeds 5-8 - two byes;
Seeds 9-14 - one bye; and
Seeds 15-18 - no byes.
The problem is, $cum's upcoming 8-gm B10 sched is much easier than UCLA's ~~~ almost 30% easier thru the 1st tiebreakers:
UCLA's 8 B10 opponents currently hold an average 6.88 cumulative Seed, far tuffer than a notably softer 9.63 $cum opponents' cumulative Seed. The main diff is we get #1 MI and #4 MiSt on the road vs them @ #18 PSU & #9 OhSt on the road.
There is an easy solution, but it hasn't been the yellow brick road in the past:
We play $cum twice and a sweep would pretty much clinch our Dance bona fides (plus, if the hoops gods are kind, maybe bounce $cum out of the Dance) over the Galens. Problem is, CMC, in his prior 6 yrs at UCLA is an uber disappointing 5-7 vs LA Trade Tech.